I scavenged an inverter off a discarded Thinkpad laptop for use in testing single CCFL bulbs. Don't know if it works yet. It is marked "ambit j071033.02" on one side and 12P3052 on the other. On the output end it has what looks like the same 2 pin socket as seen on several desktop LCD inverter boards. On the other it has a connector with 8 tiny pins. I'm trying to figure out how to wire up the input side so that it goes full on when power is applied. Just beyond the 8 pin connector there is a fuse, a capacitor and a resistor, and then a grounded mounting hole. Pin 8 is numbered. The multimeter shows the pins connected like this:
1 fuse
2 fuse
3 ground
4 ground
5 ?
6 ?
7 ground
8 ?
The resistor measures as a short, and both sides are at ground. The capacitor is wired between the fuse and the ground.
For a first pass I'm going to wire +5V (or do laptops use +12V?) to the fuse and attach ground via the grounded screw hole. If it lights up, great, if not, any thoughts on what if anything should be applied at pins 5, 6, and 8? High or low?
Thanks.
1 fuse
2 fuse
3 ground
4 ground
5 ?
6 ?
7 ground
8 ?
The resistor measures as a short, and both sides are at ground. The capacitor is wired between the fuse and the ground.
For a first pass I'm going to wire +5V (or do laptops use +12V?) to the fuse and attach ground via the grounded screw hole. If it lights up, great, if not, any thoughts on what if anything should be applied at pins 5, 6, and 8? High or low?
Thanks.
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