Dear members,
Let us consider the buck-converter circuit of +1.05VS_VCCPP in the PDF. +1.05VS_VCCPP is a 1.05v voltage rail. The schematic says the circuit can provide up to 20A of current. It belongs to a laptop: Lenovo G470. B+ is 19v.
Now assume we connect +1.05VS_VCCPP to many ICs to provide power for them. The laptop works in a way that mostly less than 20A are drawn from +1.05VS_VCCPP but sometimes the required current exceeds 20A. For example, 25A or 30A.
PU702 is the controller IC in the buck-converter circuit. It controls the output voltage according to the feedback in Pin 5.
Please explain what will happen when the connected ICs try to draw more than 20A from this buck-converter circuit?
Does the buck-converter circuit provide the extra current or it just provides 20A?
Does the voltage drops at those times?
Do the Mosfets get hot?
Does any IC get damaged at those times?
Thanks
Let us consider the buck-converter circuit of +1.05VS_VCCPP in the PDF. +1.05VS_VCCPP is a 1.05v voltage rail. The schematic says the circuit can provide up to 20A of current. It belongs to a laptop: Lenovo G470. B+ is 19v.
Now assume we connect +1.05VS_VCCPP to many ICs to provide power for them. The laptop works in a way that mostly less than 20A are drawn from +1.05VS_VCCPP but sometimes the required current exceeds 20A. For example, 25A or 30A.
PU702 is the controller IC in the buck-converter circuit. It controls the output voltage according to the feedback in Pin 5.
Please explain what will happen when the connected ICs try to draw more than 20A from this buck-converter circuit?
Does the buck-converter circuit provide the extra current or it just provides 20A?
Does the voltage drops at those times?
Do the Mosfets get hot?
Does any IC get damaged at those times?
Thanks
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